Hi all… long time no hear.. and not because I’m deaf.

I’ve got a 5-sided figure and need to know what the size would be of one particular edge if any of the other sides had their length changed. Is there some sort of formula available? Happy to play with trig if needed, sin cos and tan strike no fear in me.

Here’s the shape and dimensions:

I know how big the side is right now, but will need to work out what the size of the angled line will be if any other side was adjusted. Is this possible? And if so, how would it be calculated?

The angled line is the long side of a perpendicular triangle…

• The angled line is the long side of a perpendicular triangle…

To get the terminology right:

The angled line is the hypotenuse of a right triangle…

Call the left side L, right side R, top side T, bottom side B, and your slanting slide S.

S= sqrt( (L-R)^2 + (T-B)^2)

Thanks Furious & DV :)

Unlike the others I’d probably try to use Pythagoras’ theory and go from there.

ROFL

>Here’s the shape and dimensions

Making a harpsichord?

Bubblecar said:

>Here’s the shape and dimensions

Making a harpsichord?

:)

I’m actually working as a library developer for my bro’s cabinetmaking software company. The library is what has all the available cabinets in it, and I’m currently working on a 2-door pantry but the door (here, the hypotenuse) isn’t staying as the width it should be if the other sides have their lengths adjusted.

It’s basically playing out like a bit of programming, but with a lot more maths than I’m used to. The programming project I did last week had hardly any maths in it…

JTQ said:

Bubblecar said:

>Here’s the shape and dimensions

Making a harpsichord?

:)

I’m actually working as a library developer for my bro’s cabinetmaking software company. The library is what has all the available cabinets in it, and I’m currently working on a 2-door pantry but the door (here, the hypotenuse) isn’t staying as the width it should be if the other sides have their lengths adjusted.

It’s basically playing out like a bit of programming, but with a lot more maths than I’m used to. The programming project I did last week had hardly any maths in it…

Look, I’ve got to say…

The overall task you are describing is pretty mathsy. I wouldn’t give it to someone who didn’t have a good knowledge of geometry.

dv said:

JTQ said:

Bubblecar said:

>Here’s the shape and dimensions

Making a harpsichord?

:)

I’m actually working as a library developer for my bro’s cabinetmaking software company. The library is what has all the available cabinets in it, and I’m currently working on a 2-door pantry but the door (here, the hypotenuse) isn’t staying as the width it should be if the other sides have their lengths adjusted.

It’s basically playing out like a bit of programming, but with a lot more maths than I’m used to. The programming project I did last week had hardly any maths in it…

Look, I’ve got to say…

The overall task you are describing is pretty mathsy. I wouldn’t give it to someone who didn’t have a good knowledge of geometry.

That’s fair enough.. this one particular cabinet has this maths bit to it but besides that isn’t too bad. I’m a bit rusty with geometry but have studied a little it previously.

For what it is worth, I make it 1202.0815

PermeateFree said:

For what it is worth, I make it 1202.0815

That’s what I’ve found as well, but only with the current dimensions.

I’ve added it up like this: (Sqrt((1050-200)^2)+((1430-580)^2)) but it’s giving me an answer of 723350mm?? Surely I’ve done something wrong…?

DV’s formula was:
Call the left side L, right side R, top side T, bottom side B, and your slanting slide S.
S= sqrt( (L-R)^2 + (T-B)^2)

Original image:

Nevermind… grammatical error.

=SQRT^2)+((1430-580)^2))

grr…

=SQRT (((1050-200)^2)+((1430-580)^2))

JTQ said:

grr…

=SQRT (((1050-200)^2)+((1430-580)^2))

All and more here.
http://en.wikipedia.org/wiki/Pythagorean_theorem

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

jjjust moi said:

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

Don’t want to be picky, but isn’t it other it the other two hides?

bob(from black rock) said:

jjjust moi said:

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

Don’t want to be picky, but isn’t it other it the other two hides?

The squaw with the twins slept in the middle, in the version I heard.

jjjust moi said:

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

Where does the right-handed trimangle fit into all this?

PermeateFree said:

jjjust moi said:

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

Where does the right-handed trimangle fit into all this?

It’s an old mnemonic joke, where an indian chief has three wives, one sleeps on the middle on a hippopotomus hide, in due course she has twins while the other two only have a single birth each.

jjjust moi said:

PermeateFree said:

jjjust moi said:

The squaw on the hippopotamus is equal to the sum of the squaws on the other two sides.

Where does the right-handed trimangle fit into all this?

It’s an old mnemonic joke, where an indian chief has three wives, one sleeps on the middle on a hippopotomus hide, in due course she has twins while the other two only have a single birth each.

Ah I see, it is a right-angled hide they are sleeping on. Now it makes sense.

PermeateFree said:

jjjust moi said:

PermeateFree said:

Where does the right-handed trimangle fit into all this?

It’s an old mnemonic joke, where an indian chief has three wives, one sleeps on the middle on a hippopotomus hide, in due course she has twins while the other two only have a single birth each.

Ah I see, it is a right-angled hide they are sleeping on. Now it makes sense.

Small problem. Squaws live in North America. Hippos live in Africa.

Tamb said:

PermeateFree said:

jjjust moi said:

It’s an old mnemonic joke, where an indian chief has three wives, one sleeps on the middle on a hippopotomus hide, in due course she has twins while the other two only have a single birth each.

Ah I see, it is a right-angled hide they are sleeping on. Now it makes sense.

Small problem. Squaws live in North America. Hippos live in Africa.

Cheap Chinese import.

jjjust moi said:

Tamb said:

PermeateFree said:

Ah I see, it is a right-angled hide they are sleeping on. Now it makes sense.

Small problem. Squaws live in North America. Hippos live in Africa.

Cheap Chinese import.

The squaw or the hippo?

• Small problem. Squaws live in North America. Hippos live in Africa.

Could be one of Escobar’s Hippos got (even more) lost…

Tamb said:

jjjust moi said:

Tamb said:

Small problem. Squaws live in North America. Hippos live in Africa.

Cheap Chinese import.

The squaw or the hippo?

The hide was part of the dowry.

Heisenberg and Schrödinger are driving, and get pulled over. Heisenberg is in the driver’s seat, the officer asks “do you know how fast you were going?” Heisenberg replies, “No, but I know exactly where I am!” The officer looks at him confused and says “you were going 108 miles per hour!” Heisenberg throws his arms up and cries, “Great! Now I’m lost!”

The officer, now more confused and frustrated orders the men outside of the car, and proceeds to inspect the vehicle. He opens the trunk and yells at the two men, “Hey! Did you guys know you have a dead cat back here?” Schrödinger angrily yells back, “We do now.

The angle of the dangle is directly proportional to the heat of the meat, but inversely proportional to the sag of the bag.

ideally the constraints would off bean moor explicit